4x+2[3(x-1)+2]=8

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Solution for 4x+2[3(x-1)+2]=8 equation:


Simplifying
4x + 2[3(x + -1) + 2] = 8

Reorder the terms:
4x + 2[3(-1 + x) + 2] = 8
4x + 2[(-1 * 3 + x * 3) + 2] = 8
4x + 2[(-3 + 3x) + 2] = 8

Reorder the terms:
4x + 2[-3 + 2 + 3x] = 8

Combine like terms: -3 + 2 = -1
4x + 2[-1 + 3x] = 8
4x + [-1 * 2 + 3x * 2] = 8
4x + [-2 + 6x] = 8

Reorder the terms:
-2 + 4x + 6x = 8

Combine like terms: 4x + 6x = 10x
-2 + 10x = 8

Solving
-2 + 10x = 8

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 10x = 8 + 2

Combine like terms: -2 + 2 = 0
0 + 10x = 8 + 2
10x = 8 + 2

Combine like terms: 8 + 2 = 10
10x = 10

Divide each side by '10'.
x = 1

Simplifying
x = 1

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